1
A debtor can pay 87 cents in the dollar, but if his creditors would take 20% of his debts, he could pay them and have 42 left. His net asset is
A.
B.
C.
D.
Answer & Solution
Let, the total debt
be D & total assets be A.
The
debtor can pay 87 cents in the dollar, meaning he can pay 87%
of his total debt.
So, amount he can pay=0.87D
Since
he can only pay from his assets, A=0.87D
If
the creditors forgive 20% of his debt, he only needs to pay 80%
of it.
So, new debt to be paid=0.8D
After
paying this, he still has 42 left:
A−0.8D=42
Þ 0.87D−0.8D=42 (A=0.87D)
Þ 0.07D = 42
Þ 0.07D=42
Þ D=42/0.07=600
Now,
A=0.87D = 0.87 × 600 =522
\ Net Asset = Total Asset –
Total Debt = 522 – 600
= - 78
2
The average age of the mother and her six children is 12 years which is reduced by 5 years if the age of the mother is excluded. How old is the mother?
A.
B.
C.
D.
Answer & Solution
Age of the mother (12 × 7 - 7 × 6) years = 42
years.
3
There were 24 students in a class. One of them, who was 18 years old, left the class and his place was filled up by a newcomer. If the average of the class thereby, was lowered by one month, the age of the newcomer is
A.
B.
C.
D.
Answer & Solution
Total age decreased (24 × 1) = 24 months = 2
years.
\ Age of the newcomer =(18
- 2) = 16 years.
4
When 15 is included in a list of natural numbers, their mean is increased by 2. When 1 is included in this new list, the mean of the numbers in the new list is decreased by 1. How many numbers were there in the original list?
A.
B.
C.
D.
Answer & Solution
Let, there be n numbers in the original list
and let their mean be x.
Then, sum of n numbers = nx.
\ nx + 15 = (x + 2)(n +
1)
Þ nx + 15 = (n + 1)(x +
2)
Þ nx + 15 = nx + 2n + x
+ 2
Þ 2n + x = 13……………(i)
and, nx + 16 = (n + 2)[(x + 2) – 1]
Þ nx + 16 = (x + 2)(x +
1)
Þ nx + 16 = nx + n + 2x
+ 2
Þ n + 2x = 14…………..(ii)
Solving
(i) and (ii), we get, n = 4, x = 5
5
The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team?
A.
B.
C.
D.
Answer & Solution
Let the average age of the whole team be x
years.
\ 11x - (26 + 29) = 9(x
- 1)
Þ 11x - 9x = 46
Þ x = 23
So, the average age of the team is 23 years.
6
A batsman makes a score of 84 runs in the 21st inning and thus increases his average by 2 runs. His average after 21st inning is
A.
B.
C.
D.
Answer & Solution
Let the average for 20 innings be x.
Then, (20x + 84) = 21(x + 2)
Þ 20x + 84 = 21x + 42
Þ x = 42
\ Average after 21st
inning = 42 + 2 = 44.
7
A cricketer whose bowling average is 12.4 runs per wicket takes 5 wickets for 26 runs and thereby decreases his average by 0.4. The number of wickets taken by him till the last match was
A.
B.
C.
D.
Answer & Solution
Let the number of wickets taken till the last
match be x.
Then, 12.4x + 26 = 12(x + 5)
Þ12.4x + 26 = 12x + 60
Þ 0.4x = 34
Þ x = 85
8
A team of 8 persons joins in a shooting competition. The best marksman scored 85 points. If he had scored 92 points, the average score for the team would have been 84. The number of points, the team scored was
A.
B.
C.
D.
Answer & Solution
Let the total score be x.
\ [(x + 92) – 85]/8 =
84
Þ x + 7 = 672
Þ x = 665
9
The average age of a husband and his wife was 23 years at the time of their marriage. After five years they have a one-year old child. The average age of the family now is
A.
B.
C.
D.
Answer & Solution
Sum of the present ages of husband, wife and
child = (23 × 2 + 5 × 2) + 1 = 57 years.
\ Required average =
57/3 = 19 years.
10
After replacing an old member by a new member it was found that the average age of five member of a club is the same as it was 3 years ago. What is the difference between the ages of the replaced and the new member?
A.
B.
C.
D.
Answer & Solution
Let the initial number of persons be
x
Now, 16x + 20
×15 = 15.5(x+20)
Or, 16x –
15.5x = 310 - 300
Or, 0.5x =
10
Or, x = 20
